Table of Contents
- Three Possible Outcomes
- Case 1: No Solution (Empty Set)
- Case 2: All Real Numbers
- Case 3: Strict vs. Non-Strict at the Boundary
- How to Recognize Special Cases
- More Practice Examples
- Practice Exercises
- Related Articles
1. Three Possible Outcomes
When solving a linear inequality, there are three possible outcomes:
| Outcome | What Happens | Solution |
| Normal | Variable is isolated, e.g. x>3 | An interval, e.g. (3,∞) |
| No solution | You get a false statement, e.g. 0>5 | Empty set: ∅ |
| All real numbers | You get a true statement, e.g. 0<5 | All reals: R |
Key idea: Special cases happen when the variable cancels out completely, leaving a statement with only numbers.
2. Case 1: No Solution (Empty Set)
An inequality has no solution when simplifying leads to a false numerical statement.
Example 1
Solve: 2x+5>2x+9
Subtract 2x from both sides:
5>9
This is false --- no matter what value of x we choose, the left side will always be 4 less than the right side.
Solution: x∈∅ (no solution)
Example 2
Solve: 3(x−1)≤3x−7
Expand:
3x−3≤3x−7
Subtract 3x:
−3≤−7
This is false (−3 is greater than −7, not less).
Solution: x∈∅
Example 3
Solve: 4x+8<4(x+1)
Expand the right side:
4x+8<4x+4
Subtract 4x:
8<4
This is false.
Solution: x∈∅
3. Case 2: All Real Numbers
An inequality is satisfied by all real numbers when simplifying leads to a true numerical statement.
Example 1
Solve: 2x+5<2x+9
Subtract 2x from both sides:
5<9
This is always true --- no matter what x equals, the left side is always 4 less than the right side.
Solution: x∈(−∞,∞)=R
Example 2
Solve: 3(x+2)≥3x+1
Expand:
3x+6≥3x+1
Subtract 3x:
6≥1
This is always true.
Solution: x∈R
Example 3
Solve: x−4≤x+10
Subtract x:
−4≤10
This is always true.
Solution: x∈R
4. Case 3: Strict vs. Non-Strict at the Boundary
A subtle but important case occurs when the variable cancels out and leaves 0 compared to 0.
With Strict Inequality
Solve: 5x+3>5x+3
Subtract 5x+3:
0>0
This is false. Zero is not greater than zero.
Solution: x∈∅
With Non-Strict Inequality
Solve: 5x+3≥5x+3
Subtract 5x+3:
0≥0
This is true. Zero is equal to zero, and ≥ includes equality.
Solution: x∈R
Notice: The only difference between these two problems is the inequality symbol (> vs. ≥), but they have completely different solutions!
5. How to Recognize Special Cases
You can often spot special cases before solving completely:
Pattern 1: Identical Variable Terms
If both sides have the same x-term, the variable will cancel out.
After subtracting 2x: 3>7 --- a numerical statement.
Pattern 2: Multiplied by the Same Factor
3(x+1)≤3x+5
Expanding: 3x+3≤3x+5. Both sides have 3x, so it will cancel.
Decision Flowchart
After the variable cancels out:
- Is the resulting statement true? ⇒ Solution is R
- Is the resulting statement false? ⇒ Solution is ∅
6. More Practice Examples
Example A
Solve: −2(x+3)>−2x+1
Expand: −2x−6>−2x+1
Subtract −2x: −6>1
False. Solution: x∈∅
Example B
Solve: 2x+4≤2x+10
Subtract 2x: 4≤10
True. Solution: x∈R
Example C
Solve: 7x−7x+2<5
Simplify: 2<5
True. Solution: x∈R
Example D
Solve: x+x−2x≥1
Simplify: 0≥1
False. Solution: x∈∅
Practice Exercises
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