Prisms in grade 7 — decimal edges and triangular prism

Prisms in grade 7 — decimal edges and triangular prism

Prisms in grade 7

In grade 6 you learned to compute the surface area and volume of a cuboid and a cube with whole-number edges. In grade 7 two new layers come on top:

  1. Decimal edges — the same formula, with more careful arithmetic.
  2. Other types of prism — especially the triangular prism, whose base is not a rectangle.

1) Cuboid surface area with decimal edges

The formula stays the same:

S = 2 · (a·b + b·c + a·c)

Example: `a = 2.5 cm`, `b = 4 cm`, `c = 6 cm`.

stepcomputationresult
a·b`2.5 · 4``10 cm²`
b·c`4 · 6``24 cm²`
a·c`2.5 · 6``15 cm²`
sum`10 + 24 + 15``49 cm²`
× 2`2 · 49`98 cm²
Tips for decimals:
  • Multiply first whichever pair has only one decimal (e.g. `2.5 · 4`) — that's always easy.
  • When multiplying two decimals (e.g. `2.5 · 1.5`), help yourself with fractions: `5/2 · 3/2 = 15/4 = 3.75`.
  • Check the unit at the end — surface area is always in square units (cm², m²).

2) Volume of a triangular prism

For any prism the same general formula holds:

V = Sp · hp

where `S_p` is the base area and `h_p` is the prism height (distance between the two parallel bases).

For a triangular prism you first compute the area of the triangular base:

Sp = (a · h) / 2

Example: base side `a = 6 cm`, triangle height `h_△ = 4 cm`, prism height `h_p = 10 cm`.

  1. Base area: `S_p = (6 · 4) / 2 = 12 cm²`.
  2. Volume: `V = 12 · 10 = 120 cm³`.

Don't mix up the two heights: `h_△` is the height of the triangle (perpendicular from a side to the opposite vertex), `h_p` is the height of the prism (distance between the two bases). They often have different values.

A common schema for volume

prism typebase areavolume
cuboid (a × b)`a · b``a · b · c`
cube (a)`a²``a³`
triangular (a, h_△)`(a · h_△) / 2``(a · h_△ · h_p) / 2`
other (S_p given)`S_p``S_p · h_p`

Try it yourself