Word problems with ratios and the rule of three

Word problems with ratios and the rule of three

Word problems with ratios and the rule of three

Ratios and the rule of three are two of the workhorses of grade 7. A ratio tells you "in what proportion" something is split; the rule of three answers "how much do I get for a different amount".

Two-part ratio

Problem. Mia and Jay share £60 in the ratio 2 : 3. How much more does the bigger share get?

Working:

  1. Sum of the parts: `2 + 3 = 5` parts.
  2. One part is worth: `60 / 5 = £12`.
  3. Smaller share: `2 · 12 = £24`. Bigger share: `3 · 12 = £36`.
  4. Difference: `36 − 24 = £12`.

Three-part ratio

Problem. A profit of £90 is split in the ratio 1 : 2 : 3. How much is the middle share?

Working:

  1. Sum: `1 + 2 + 3 = 6` parts.
  2. One part: `90 / 6 = £15`.
  3. Middle share: `2 · 15 = £30`.

Rule of three — direct proportion

Direct proportion: if quantity A is multiplied by `k`, then quantity B is also multiplied by `k`. Symbolically: `A1 / B1 = A2 / B2`.

Problem. 4 notebooks cost £6. How much do 10 notebooks cost?

Working:

  • One notebook costs `6 / 4 = £1.50`.
  • 10 notebooks cost `10 · 1.50 = £15`.

Rule of three — inverse proportion

Inverse proportion: if quantity A is multiplied by `k`, then quantity B is divided by `k`. The product `A · B` stays the same.

Problem. 3 workers finish a job in 12 days. How long would 6 workers take at the same pace?

Working:

  • Total work = `3 · 12 = 36` worker-days.
  • With 6 workers: `36 / 6 = 6` days.

How to spot direct vs. inverse?

  • More of one → more of the other: direct (price, fuel, mass).
  • More of one → less of the other: inverse (workers and days, speed and time).

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